-952(2w^2)=0

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Solution for -952(2w^2)=0 equation: 



-952(2w^2)=0

a = -9522; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-9522)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-19044}=0$

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